Base | Representation |
---|---|
bin | 110011001111111010… |
… | …0000011001101101111 |
3 | 101112001221122210220212 |
4 | 1212133310003031233 |
5 | 3300343140420044 |
6 | 122320405133035 |
7 | 10644163334213 |
oct | 1463764031557 |
9 | 345057583825 |
10 | 110055404399 |
11 | 42746452276 |
12 | 193b53ba17b |
13 | a4bbb28185 |
14 | 54806c6943 |
15 | 2ce1ddda9e |
hex | 199fd0336f |
110055404399 has 2 divisors, whose sum is σ = 110055404400. Its totient is φ = 110055404398.
The previous prime is 110055404351. The next prime is 110055404401. The reversal of 110055404399 is 993404550011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110055404399 - 28 = 110055404143 is a prime.
It is a super-2 number, since 2×1100554043992 (a number of 23 digits) contains 22 as substring.
Together with 110055404401, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110055406399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55027702199 + 55027702200.
It is an arithmetic number, because the mean of its divisors is an integer number (55027702200).
Almost surely, 2110055404399 is an apocalyptic number.
110055404399 is a deficient number, since it is larger than the sum of its proper divisors (1).
110055404399 is an equidigital number, since it uses as much as digits as its factorization.
110055404399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 41.
The spelling of 110055404399 in words is "one hundred ten billion, fifty-five million, four hundred four thousand, three hundred ninety-nine".
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