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11005543207 is a prime number
BaseRepresentation
bin10100011111111101…
…10100001100100111
31001101222212112002101
422033332310030213
5140014404340312
65020022552531
7536504400541
oct121776641447
931358775071
1011005543207
11473838455a
122171898747
131065118759
14765914691
154462d6a57
hex28ffb4327

11005543207 has 2 divisors, whose sum is σ = 11005543208. Its totient is φ = 11005543206.

The previous prime is 11005543183. The next prime is 11005543253. The reversal of 11005543207 is 70234550011.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (70234550011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11005543207 - 211 = 11005541159 is a prime.

It is a super-2 number, since 2×110055432072 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11005543277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502771603 + 5502771604.

It is an arithmetic number, because the mean of its divisors is an integer number (5502771604).

Almost surely, 211005543207 is an apocalyptic number.

11005543207 is a deficient number, since it is larger than the sum of its proper divisors (1).

11005543207 is an equidigital number, since it uses as much as digits as its factorization.

11005543207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4200, while the sum is 28.

The spelling of 11005543207 in words is "eleven billion, five million, five hundred forty-three thousand, two hundred seven".