Base | Representation |
---|---|
bin | 10100011111111101… |
… | …10100001100100111 |
3 | 1001101222212112002101 |
4 | 22033332310030213 |
5 | 140014404340312 |
6 | 5020022552531 |
7 | 536504400541 |
oct | 121776641447 |
9 | 31358775071 |
10 | 11005543207 |
11 | 473838455a |
12 | 2171898747 |
13 | 1065118759 |
14 | 765914691 |
15 | 4462d6a57 |
hex | 28ffb4327 |
11005543207 has 2 divisors, whose sum is σ = 11005543208. Its totient is φ = 11005543206.
The previous prime is 11005543183. The next prime is 11005543253. The reversal of 11005543207 is 70234550011.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (70234550011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11005543207 - 211 = 11005541159 is a prime.
It is a super-2 number, since 2×110055432072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11005543277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502771603 + 5502771604.
It is an arithmetic number, because the mean of its divisors is an integer number (5502771604).
Almost surely, 211005543207 is an apocalyptic number.
11005543207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11005543207 is an equidigital number, since it uses as much as digits as its factorization.
11005543207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 28.
The spelling of 11005543207 in words is "eleven billion, five million, five hundred forty-three thousand, two hundred seven".
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