Base | Representation |
---|---|
bin | 1010000000101010001110… |
… | …1111011110110010111111 |
3 | 1102222012120122202121001122 |
4 | 2200022203233132302333 |
5 | 2420312204024023341 |
6 | 35224143405101155 |
7 | 2214122113543523 |
oct | 240124357366277 |
9 | 42865518677048 |
10 | 11006453345471 |
11 | 35638a0a80981 |
12 | 129915ab577bb |
13 | 61ab9a3bb47c |
14 | 2a0a02673d83 |
15 | 141482ee194b |
hex | a02a3bdecbf |
11006453345471 has 2 divisors, whose sum is σ = 11006453345472. Its totient is φ = 11006453345470.
The previous prime is 11006453345431. The next prime is 11006453345497. The reversal of 11006453345471 is 17454335460011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11006453345471 is a prime.
It is a super-3 number, since 3×110064533454713 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11006453345431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503226672735 + 5503226672736.
It is an arithmetic number, because the mean of its divisors is an integer number (5503226672736).
Almost surely, 211006453345471 is an apocalyptic number.
11006453345471 is a deficient number, since it is larger than the sum of its proper divisors (1).
11006453345471 is an equidigital number, since it uses as much as digits as its factorization.
11006453345471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 44.
The spelling of 11006453345471 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred forty-five thousand, four hundred seventy-one".
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