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11006453345431 is a prime number
BaseRepresentation
bin1010000000101010001110…
…1111011110110010010111
31102222012120122202121000011
42200022203233132302113
52420312204024023211
635224143405101051
72214122113543435
oct240124357366227
942865518677004
1011006453345431
1135638a0a80945
12129915ab57787
1361ab9a3bb44b
142a0a02673d55
15141482ee1921
hexa02a3bdec97

11006453345431 has 2 divisors, whose sum is σ = 11006453345432. Its totient is φ = 11006453345430.

The previous prime is 11006453345429. The next prime is 11006453345471. The reversal of 11006453345431 is 13454335460011.

It is an a-pointer prime, because the next prime (11006453345471) can be obtained adding 11006453345431 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11006453345431 - 21 = 11006453345429 is a prime.

It is a super-2 number, since 2×110064533454312 (a number of 27 digits) contains 22 as substring.

Together with 11006453345429, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11006453345471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5503226672715 + 5503226672716.

It is an arithmetic number, because the mean of its divisors is an integer number (5503226672716).

Almost surely, 211006453345431 is an apocalyptic number.

11006453345431 is a deficient number, since it is larger than the sum of its proper divisors (1).

11006453345431 is an equidigital number, since it uses as much as digits as its factorization.

11006453345431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 40.

The spelling of 11006453345431 in words is "eleven trillion, six billion, four hundred fifty-three million, three hundred forty-five thousand, four hundred thirty-one".