Base | Representation |
---|---|
bin | 1010000000101010010010… |
… | …0001101011011000010111 |
3 | 1102222012121120112010110112 |
4 | 2200022210201223120113 |
5 | 2420312220411113330 |
6 | 35224144555113235 |
7 | 2214122333440310 |
oct | 240124441533027 |
9 | 42865546463415 |
10 | 11006466504215 |
11 | 35638a8449276 |
12 | 129916344281b |
13 | 61aba0047a00 |
14 | 2a0a042db607 |
15 | 141484240795 |
hex | a02a486b617 |
11006466504215 has 48 divisors (see below), whose sum is σ = 16351690060800. Its totient is φ = 6963888087936.
The previous prime is 11006466504191. The next prime is 11006466504277. The reversal of 11006466504215 is 51240566460011.
It is not a de Polignac number, because 11006466504215 - 214 = 11006466487831 is a prime.
It is a super-3 number, since 3×110064665042153 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14166626 + ... + 14923344.
It is an arithmetic number, because the mean of its divisors is an integer number (340660209600).
Almost surely, 211006466504215 is an apocalyptic number.
11006466504215 is a deficient number, since it is larger than the sum of its proper divisors (5345223556585).
11006466504215 is a wasteful number, since it uses less digits than its factorization.
11006466504215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 759216 (or 759203 counting only the distinct ones).
The product of its (nonzero) digits is 172800, while the sum is 41.
The spelling of 11006466504215 in words is "eleven trillion, six billion, four hundred sixty-six million, five hundred four thousand, two hundred fifteen".
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