1100811314400 has 1152 divisors, whose sum is σ = 4535709696000. Its totient is φ = 226221465600.

The previous prime is 1100811314399. The next prime is 1100811314413. The reversal of 1100811314400 is 44131180011.

It is a super-2 number, since 2×1100811314400² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 524444551 + ... + 524446649.

It is an arithmetic number, because the mean of its divisors is an integer number (3937248000).

Almost surely, 2^{1100811314400} is an apocalyptic number.

1100811314400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1100811314400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2267854848000).

1100811314400 is an abundant number, since it is smaller than the sum of its proper divisors (3434898381600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1100811314400 is a wasteful number, since it uses less digits than its factorization.

1100811314400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2232 (or 2219 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 24.

Adding to 1100811314400 its reverse (44131180011), we get a palindrome (1144942494411).

The spelling of 1100811314400 in words is "one trillion, one hundred billion, eight hundred eleven million, three hundred fourteen thousand, four hundred".