Base | Representation |
---|---|
bin | 10000000001011000101… |
… | …110100001111000010111 |
3 | 10220020212121011012212201 |
4 | 100001120232201320113 |
5 | 121014322024021213 |
6 | 2201443103425331 |
7 | 142354545313243 |
oct | 20013056417027 |
9 | 3806777135781 |
10 | 1101000220183 |
11 | 394a27a15246 |
12 | 15946a8b5247 |
13 | 7ca93091736 |
14 | 3b408271423 |
15 | 1d98d6c76dd |
hex | 10058ba1e17 |
1101000220183 has 2 divisors, whose sum is σ = 1101000220184. Its totient is φ = 1101000220182.
The previous prime is 1101000220163. The next prime is 1101000220207. The reversal of 1101000220183 is 3810220001011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1101000220183 - 221 = 1100998123031 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1101000220183.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101000220163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550500110091 + 550500110092.
It is an arithmetic number, because the mean of its divisors is an integer number (550500110092).
Almost surely, 21101000220183 is an apocalyptic number.
1101000220183 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101000220183 is an equidigital number, since it uses as much as digits as its factorization.
1101000220183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1101000220183 its reverse (3810220001011), we get a palindrome (4911220221194).
The spelling of 1101000220183 in words is "one trillion, one hundred one billion, two hundred twenty thousand, one hundred eighty-three".
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