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11010011009981 is a prime number
BaseRepresentation
bin1010000000110111011111…
…0010111001001110111101
31102222112202121010200021212
42200031313302321032331
52420342000304304411
635225532414134205
72214306223312334
oct240156762711675
942875677120255
1011010011009981
113565357203985
1212999924b1365
1361b3164979b9
142a0c5cd62d1b
151415e04de68b
hexa0377cb93bd

11010011009981 has 2 divisors, whose sum is σ = 11010011009982. Its totient is φ = 11010011009980.

The previous prime is 11010011009969. The next prime is 11010011009983. The reversal of 11010011009981 is 18990011001011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6354730097881 + 4655280912100 = 2520859^2 + 2157610^2 .

It is an emirp because it is prime and its reverse (18990011001011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11010011009981 is a prime.

It is a super-2 number, since 2×110100110099812 (a number of 27 digits) contains 22 as substring.

Together with 11010011009983, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11010011009983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505005504990 + 5505005504991.

It is an arithmetic number, because the mean of its divisors is an integer number (5505005504991).

Almost surely, 211010011009981 is an apocalyptic number.

It is an amenable number.

11010011009981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010011009981 is an equidigital number, since it uses as much as digits as its factorization.

11010011009981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 32.

The spelling of 11010011009981 in words is "eleven trillion, ten billion, eleven million, nine thousand, nine hundred eighty-one".