Base | Representation |
---|---|
bin | 11001000010001010101110… |
… | …000000110000110001011111 |
3 | 112102211110122001020122022111 |
4 | 121002022232000300301133 |
5 | 103412340011420213043 |
6 | 1030055143124054451 |
7 | 32122320251034001 |
oct | 3102125600606137 |
9 | 472743561218274 |
10 | 110100111101023 |
11 | 3209921645a11a |
12 | 10422180534427 |
13 | 495851bb10444 |
14 | 1d28c33a42371 |
15 | cade5359609d |
hex | 6422ae030c5f |
110100111101023 has 2 divisors, whose sum is σ = 110100111101024. Its totient is φ = 110100111101022.
The previous prime is 110100111100981. The next prime is 110100111101153. The reversal of 110100111101023 is 320101111001011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110100111101023 - 241 = 107901087845471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 110100111100994 and 110100111101012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110100111101423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050055550511 + 55050055550512.
It is an arithmetic number, because the mean of its divisors is an integer number (55050055550512).
Almost surely, 2110100111101023 is an apocalyptic number.
110100111101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
110100111101023 is an equidigital number, since it uses as much as digits as its factorization.
110100111101023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 13.
Adding to 110100111101023 its reverse (320101111001011), we get a palindrome (430201222102034).
The spelling of 110100111101023 in words is "one hundred ten trillion, one hundred billion, one hundred eleven million, one hundred one thousand, twenty-three".
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