110101000117 has 2 divisors, whose sum is σ = 110101000118. Its totient is φ = 110101000116.

The previous prime is 110101000111. The next prime is 110101000151. The reversal of 110101000117 is 711000101011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 105244443396 + 4856556721 = 324414^2 + 69689^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110101000117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110101000097 and 110101000106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110101000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050500058 + 55050500059.

It is an arithmetic number, because the mean of its divisors is an integer number (55050500059).

Almost surely, 2^110101000117 is an apocalyptic number.

It is an amenable number.

110101000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

110101000117 is an equidigital number, since it uses as much as digits as its factorization.

110101000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7, while the sum is 13.

Adding to 110101000117 its reverse (711000101011), we get a palindrome (821101101128).

The spelling of 110101000117 in words is "one hundred ten billion, one hundred one million, one hundred seventeen", and thus it is an aban number.