Base | Representation |
---|---|
bin | 11001000010001011101001… |
… | …100011010011010011111011 |
3 | 112102211120012122212112101011 |
4 | 121002023221203103103323 |
5 | 103412344033130324011 |
6 | 1030055430210134351 |
7 | 32122354100445241 |
oct | 3102135143232373 |
9 | 472746178775334 |
10 | 110101110011131 |
11 | 320996892a9068 |
12 | 104223bab813b7 |
13 | 495864aa58505 |
14 | 1d28cca588791 |
15 | cadeb110e621 |
hex | 6422e98d34fb |
110101110011131 has 2 divisors, whose sum is σ = 110101110011132. Its totient is φ = 110101110011130.
The previous prime is 110101110010979. The next prime is 110101110011257. The reversal of 110101110011131 is 131110011101011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (131110011101011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110101110011131 - 229 = 110100573140219 is a prime.
It is a super-2 number, since 2×1101011100111312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110101110611131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050555005565 + 55050555005566.
It is an arithmetic number, because the mean of its divisors is an integer number (55050555005566).
Almost surely, 2110101110011131 is an apocalyptic number.
110101110011131 is a deficient number, since it is larger than the sum of its proper divisors (1).
110101110011131 is an equidigital number, since it uses as much as digits as its factorization.
110101110011131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 13.
Adding to 110101110011131 its reverse (131110011101011), we get a palindrome (241211121112142).
The spelling of 110101110011131 in words is "one hundred ten trillion, one hundred one billion, one hundred ten million, eleven thousand, one hundred thirty-one".
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