Base | Representation |
---|---|
bin | 1010000000111000001100… |
… | …1000000110110111010101 |
3 | 1102222120020211212021111120 |
4 | 2200032003020012313111 |
5 | 2420342342441321323 |
6 | 35230003324554153 |
7 | 2214314022236511 |
oct | 240160310066725 |
9 | 42876224767446 |
10 | 11010201120213 |
11 | 3565444551579 |
12 | 1299a260b2959 |
13 | 61b34699b669 |
14 | 2a0c7a2cd141 |
15 | 1416020435e3 |
hex | a0383206dd5 |
11010201120213 has 64 divisors (see below), whose sum is σ = 15882963812352. Its totient is φ = 6766240504320.
The previous prime is 11010201120211. The next prime is 11010201120223. The reversal of 11010201120213 is 31202110201011.
It is not a de Polignac number, because 11010201120213 - 21 = 11010201120211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11010201120192 and 11010201120201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11010201120211) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 113567706 + ... + 113664612.
It is an arithmetic number, because the mean of its divisors is an integer number (248171309568).
Almost surely, 211010201120213 is an apocalyptic number.
It is an amenable number.
11010201120213 is a deficient number, since it is larger than the sum of its proper divisors (4872762692139).
11010201120213 is a wasteful number, since it uses less digits than its factorization.
11010201120213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97394.
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 11010201120213 its reverse (31202110201011), we get a palindrome (42212311321224).
The spelling of 11010201120213 in words is "eleven trillion, ten billion, two hundred one million, one hundred twenty thousand, two hundred thirteen".
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