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110103443141 is a prime number
BaseRepresentation
bin110011010001010101…
…1010011011011000101
3101112012022001102200112
41212202223103123011
53300442440140031
6122325242522405
710645315552646
oct1464253233305
9345168042615
10110103443141
114277058350a
1219409506405
13a4c8a77973
145486c2d6cd
152ce622c62b
hex19a2ad36c5

110103443141 has 2 divisors, whose sum is σ = 110103443142. Its totient is φ = 110103443140.

The previous prime is 110103443119. The next prime is 110103443147. The reversal of 110103443141 is 141344301011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71251091041 + 38852352100 = 266929^2 + 197110^2 .

It is a cyclic number.

It is not a de Polignac number, because 110103443141 - 214 = 110103426757 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110103443147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55051721570 + 55051721571.

It is an arithmetic number, because the mean of its divisors is an integer number (55051721571).

Almost surely, 2110103443141 is an apocalyptic number.

It is an amenable number.

110103443141 is a deficient number, since it is larger than the sum of its proper divisors (1).

110103443141 is an equidigital number, since it uses as much as digits as its factorization.

110103443141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 110103443141 its reverse (141344301011), we get a palindrome (251447744152).

The spelling of 110103443141 in words is "one hundred ten billion, one hundred three million, four hundred forty-three thousand, one hundred forty-one".