110109113 has 2 divisors, whose sum is σ = 110109114. Its totient is φ = 110109112.

The previous prime is 110109091. The next prime is 110109133. The reversal of 110109113 is 311901011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103286569 + 6822544 = 10163^2 + 2612^2 .

It is an emirp because it is prime and its reverse (311901011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110109113 - 2²⁰ = 109060537 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 110109091 and 110109100.

It is not a weakly prime, because it can be changed into another prime (110109133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55054556 + 55054557.

It is an arithmetic number, because the mean of its divisors is an integer number (55054557).

Almost surely, 2^110109113 is an apocalyptic number.

It is an amenable number.

110109113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110109113 is an equidigital number, since it uses as much as digits as its factorization.

110109113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 17.

The square root of 110109113 is about 10493.2889505626. The cubic root of 110109113 is about 479.3003594719.

The spelling of 110109113 in words is "one hundred ten million, one hundred nine thousand, one hundred thirteen".