110110000000031 has 2 divisors, whose sum is σ = 110110000000032. Its totient is φ = 110110000000030.

The previous prime is 110109999999997. The next prime is 110110000000057. The reversal of 110110000000031 is 130000000011011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110110000000031 - 2¹⁴ = 110109999983647 is a prime.

It is a super-2 number, since 2×110110000000031² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110109999999946 and 110110000000018.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110110050000031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055000000015 + 55055000000016.

It is an arithmetic number, because the mean of its divisors is an integer number (55055000000016).

Almost surely, 2^{110110000000031} is an apocalyptic number.

110110000000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

110110000000031 is an equidigital number, since it uses as much as digits as its factorization.

110110000000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 110110000000031 its reverse (130000000011011), we get a palindrome (240110000011042).

The spelling of 110110000000031 in words is "one hundred ten trillion, one hundred ten billion, thirty-one", and thus it is an aban number.