Base | Representation |
---|---|
bin | 10000000001011110101… |
… | …011100101010011111111 |
3 | 10220021010120010012110102 |
4 | 100001132223211103333 |
5 | 121020023112023403 |
6 | 2201501032431315 |
7 | 142360200342356 |
oct | 20013653452377 |
9 | 3807116105412 |
10 | 1101100111103 |
11 | 394a79341823 |
12 | 15949824853b |
13 | 7caaa9976a5 |
14 | 3b41763499d |
15 | 1d997359b88 |
hex | 1005eae54ff |
1101100111103 has 2 divisors, whose sum is σ = 1101100111104. Its totient is φ = 1101100111102.
The previous prime is 1101100111043. The next prime is 1101100111109. The reversal of 1101100111103 is 3011110011011.
It is a strong prime.
It is an emirp because it is prime and its reverse (3011110011011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1101100111103 - 210 = 1101100110079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101100111109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550550055551 + 550550055552.
It is an arithmetic number, because the mean of its divisors is an integer number (550550055552).
Almost surely, 21101100111103 is an apocalyptic number.
1101100111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101100111103 is an equidigital number, since it uses as much as digits as its factorization.
1101100111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 1101100111103 its reverse (3011110011011), we get a palindrome (4112210122114).
The spelling of 1101100111103 in words is "one trillion, one hundred one billion, one hundred million, one hundred eleven thousand, one hundred three".
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