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1101100119997 is a prime number
BaseRepresentation
bin10000000001011110101…
…011100111011110111101
310220021010120010122122211
4100001132223213132331
5121020023112314442
62201501032540421
7142360200410323
oct20013653473675
93807116118584
101101100119997
11394a79348479
12159498251711
137caaa99b757
143b417637d13
151d99735c617
hex1005eae77bd

1101100119997 has 2 divisors, whose sum is σ = 1101100119998. Its totient is φ = 1101100119996.

The previous prime is 1101100119953. The next prime is 1101100120009. The reversal of 1101100119997 is 7999110011011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007973832441 + 93126287556 = 1003979^2 + 305166^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101100119997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101100111997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550550059998 + 550550059999.

It is an arithmetic number, because the mean of its divisors is an integer number (550550059999).

Almost surely, 21101100119997 is an apocalyptic number.

It is an amenable number.

1101100119997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101100119997 is an equidigital number, since it uses as much as digits as its factorization.

1101100119997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5103, while the sum is 40.

The spelling of 1101100119997 in words is "one trillion, one hundred one billion, one hundred million, one hundred nineteen thousand, nine hundred ninety-seven".