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11011003153 is a prime number
BaseRepresentation
bin10100100000100111…
…01001001100010001
31001102101010220201121
422100103221030101
5140022304100103
65020340002241
7536601661003
oct122023511421
931371126647
1011011003153
114740473707
122173690381
1310662aa9a7
14766536373
15446a146bd
hex2904e9311

11011003153 has 2 divisors, whose sum is σ = 11011003154. Its totient is φ = 11011003152.

The previous prime is 11011003151. The next prime is 11011003229. The reversal of 11011003153 is 35130011011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6318342144 + 4692661009 = 79488^2 + 68503^2 .

It is a cyclic number.

It is not a de Polignac number, because 11011003153 - 21 = 11011003151 is a prime.

Together with 11011003151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11011003151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505501576 + 5505501577.

It is an arithmetic number, because the mean of its divisors is an integer number (5505501577).

Almost surely, 211011003153 is an apocalyptic number.

It is an amenable number.

11011003153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011003153 is an equidigital number, since it uses as much as digits as its factorization.

11011003153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 45, while the sum is 16.

Adding to 11011003153 its reverse (35130011011), we get a palindrome (46141014164).

The spelling of 11011003153 in words is "eleven billion, eleven million, three thousand, one hundred fifty-three".