11011011101113 has 2 divisors, whose sum is σ = 11011011101114. Its totient is φ = 11011011101112.

The previous prime is 11011011101107. The next prime is 11011011101149. The reversal of 11011011101113 is 31110111011011.

It is a happy number.

11011011101113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10885697225104 + 125313876009 = 3299348^2 + 353997^2 .

It is an emirp because it is prime and its reverse (31110111011011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11011011101113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11011011101093 and 11011011101102.

It is not a weakly prime, because it can be changed into another prime (11011011101173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505505550556 + 5505505550557.

It is an arithmetic number, because the mean of its divisors is an integer number (5505505550557).

Almost surely, 2^{11011011101113} is an apocalyptic number.

It is an amenable number.

11011011101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011011101113 is an equidigital number, since it uses as much as digits as its factorization.

11011011101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 13.

Adding to 11011011101113 its reverse (31110111011011), we get a palindrome (42121122112124).

The spelling of 11011011101113 in words is "eleven trillion, eleven billion, eleven million, one hundred one thousand, one hundred thirteen".