Base | Representation |
---|---|
bin | 110011010001100010… |
… | …0110100000101000111 |
3 | 101112012202122012000121 |
4 | 1212203010310011013 |
5 | 3301001143134003 |
6 | 122330042122411 |
7 | 10645426444432 |
oct | 1464304640507 |
9 | 345182565017 |
10 | 110110130503 |
11 | 4277433085a |
12 | 1940b7b0407 |
13 | a4ca279799 |
14 | 5487a90819 |
15 | 2ce6aedcbd |
hex | 19a3134147 |
110110130503 has 2 divisors, whose sum is σ = 110110130504. Its totient is φ = 110110130502.
The previous prime is 110110130497. The next prime is 110110130519. The reversal of 110110130503 is 305031011011.
It is an a-pointer prime, because the next prime (110110130519) can be obtained adding 110110130503 to its sum of digits (16).
It is a weak prime.
It is an emirp because it is prime and its reverse (305031011011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110110130503 - 29 = 110110129991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110110133503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55055065251 + 55055065252.
It is an arithmetic number, because the mean of its divisors is an integer number (55055065252).
Almost surely, 2110110130503 is an apocalyptic number.
110110130503 is a deficient number, since it is larger than the sum of its proper divisors (1).
110110130503 is an equidigital number, since it uses as much as digits as its factorization.
110110130503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45, while the sum is 16.
Adding to 110110130503 its reverse (305031011011), we get a palindrome (415141141514).
The spelling of 110110130503 in words is "one hundred ten billion, one hundred ten million, one hundred thirty thousand, five hundred three".
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