Search a number
-
+
11011101110041 is a prime number
BaseRepresentation
bin1010000000111011100011…
…0001010010111100011001
31102222122120120100111110011
42200032320301102330121
52420401213341010131
635230232514521521
72214345231103534
oct240167061227431
942878516314404
1011011101110041
11356586657721a
12129a0375962a1
1361b45b290516
142a0d23a45a1b
1514165606c0b1
hexa03b8c52f19

11011101110041 has 2 divisors, whose sum is σ = 11011101110042. Its totient is φ = 11011101110040.

The previous prime is 11011101109849. The next prime is 11011101110117. The reversal of 11011101110041 is 14001110111011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9043732998400 + 1967368111641 = 3007280^2 + 1402629^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11011101110041 is a prime.

It is a super-2 number, since 2×110111011100412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11011101150041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505550555020 + 5505550555021.

It is an arithmetic number, because the mean of its divisors is an integer number (5505550555021).

Almost surely, 211011101110041 is an apocalyptic number.

It is an amenable number.

11011101110041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11011101110041 is an equidigital number, since it uses as much as digits as its factorization.

11011101110041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 11011101110041 its reverse (14001110111011), we get a palindrome (25012211221052).

The spelling of 11011101110041 in words is "eleven trillion, eleven billion, one hundred one million, one hundred ten thousand, forty-one".