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110113030220191 is a prime number
BaseRepresentation
bin11001000010010110110000…
…000011010010100110011111
3112102212200222101211220010121
4121002112300003102212133
5103413042441214021231
61030105121105415411
732123255352526315
oct3102266003224637
9472780871756117
10110113030220191
11320a3745a11609
121042478703a567
1349597ca503b5b
141d296db7560b5
15cae45c86d311
hex6425b00d299f

110113030220191 has 2 divisors, whose sum is σ = 110113030220192. Its totient is φ = 110113030220190.

The previous prime is 110113030220111. The next prime is 110113030220201. The reversal of 110113030220191 is 191022030311011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110113030220191 - 215 = 110113030187423 is a prime.

It is a super-3 number, since 3×1101130302201913 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110113030220111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55056515110095 + 55056515110096.

It is an arithmetic number, because the mean of its divisors is an integer number (55056515110096).

Almost surely, 2110113030220191 is an apocalyptic number.

110113030220191 is a deficient number, since it is larger than the sum of its proper divisors (1).

110113030220191 is an equidigital number, since it uses as much as digits as its factorization.

110113030220191 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 25.

The spelling of 110113030220191 in words is "one hundred ten trillion, one hundred thirteen billion, thirty million, two hundred twenty thousand, one hundred ninety-one".