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11011312133 = 40072748019
BaseRepresentation
bin10100100000101001…
…10100101000000101
31001102101201121120022
422100110310220011
5140022343442013
65020350344525
7536604415553
oct122024645005
931371647508
1011011312133
114740664868
1221737bb145
131066388513
147665b6bd3
15446a76008
hex290534a05

11011312133 has 4 divisors (see below), whose sum is σ = 11014064160. Its totient is φ = 11008560108.

The previous prime is 11011312111. The next prime is 11011312187. The reversal of 11011312133 is 33121311011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33121311011 = 113293108947.

It is a cyclic number.

It is not a de Polignac number, because 11011312133 - 26 = 11011312069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11011314133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1370003 + ... + 1378016.

It is an arithmetic number, because the mean of its divisors is an integer number (2753516040).

Almost surely, 211011312133 is an apocalyptic number.

It is an amenable number.

11011312133 is a deficient number, since it is larger than the sum of its proper divisors (2752027).

11011312133 is an equidigital number, since it uses as much as digits as its factorization.

11011312133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2752026.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 11011312133 its reverse (33121311011), we get a palindrome (44132623144).

The spelling of 11011312133 in words is "eleven billion, eleven million, three hundred twelve thousand, one hundred thirty-three".

Divisors: 1 4007 2748019 11011312133