Base | Representation |
---|---|
bin | 11001000010011110001011… |
… | …000101101010101111111011 |
3 | 112102220110112211102201111212 |
4 | 121002132023011222233323 |
5 | 103413210302001132422 |
6 | 1030112520010113335 |
7 | 32123660015651204 |
oct | 3102361305525773 |
9 | 472813484381455 |
10 | 110121000020987 |
11 | 320a706573293a |
12 | 1042623011b84b |
13 | 495a49a702407 |
14 | 1d29c55ddc5ab |
15 | cae7773a09e2 |
hex | 64278b16abfb |
110121000020987 has 2 divisors, whose sum is σ = 110121000020988. Its totient is φ = 110121000020986.
The previous prime is 110121000020861. The next prime is 110121000020989. The reversal of 110121000020987 is 789020000121011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110121000020987 - 212 = 110121000016891 is a prime.
It is a super-4 number, since 4×1101210000209874 (a number of 57 digits) contains 4444 as substring.
Together with 110121000020989, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (110121000020989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060500010493 + 55060500010494.
It is an arithmetic number, because the mean of its divisors is an integer number (55060500010494).
Almost surely, 2110121000020987 is an apocalyptic number.
110121000020987 is a deficient number, since it is larger than the sum of its proper divisors (1).
110121000020987 is an equidigital number, since it uses as much as digits as its factorization.
110121000020987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 32.
Adding to 110121000020987 its reverse (789020000121011), we get a palindrome (899141000141998).
The spelling of 110121000020987 in words is "one hundred ten trillion, one hundred twenty-one billion, twenty thousand, nine hundred eighty-seven".
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