11012100101113 has 2 divisors, whose sum is σ = 11012100101114. Its totient is φ = 11012100101112.

The previous prime is 11012100101087. The next prime is 11012100101129. The reversal of 11012100101113 is 31110100121011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10900912532409 + 111187568704 = 3301653^2 + 333448^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012100101113 - 2¹³ = 11012100092921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11012100101093 and 11012100101102.

It is not a weakly prime, because it can be changed into another prime (11012100101143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506050050556 + 5506050050557.

It is an arithmetic number, because the mean of its divisors is an integer number (5506050050557).

Almost surely, 2^{11012100101113} is an apocalyptic number.

It is an amenable number.

11012100101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012100101113 is an equidigital number, since it uses as much as digits as its factorization.

11012100101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 11012100101113 its reverse (31110100121011), we get a palindrome (42122200222124).

The spelling of 11012100101113 in words is "eleven trillion, twelve billion, one hundred million, one hundred one thousand, one hundred thirteen".