11012100101143 has 2 divisors, whose sum is σ = 11012100101144. Its totient is φ = 11012100101142.

The previous prime is 11012100101129. The next prime is 11012100101161. The reversal of 11012100101143 is 34110100121011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11012100101143 is a prime.

It is a super-4 number, since 4×11012100101143⁴ (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11012100101113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506050050571 + 5506050050572.

It is an arithmetic number, because the mean of its divisors is an integer number (5506050050572).

Almost surely, 2^{11012100101143} is an apocalyptic number.

11012100101143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012100101143 is an equidigital number, since it uses as much as digits as its factorization.

11012100101143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 11012100101143 its reverse (34110100121011), we get a palindrome (45122200222154).

The spelling of 11012100101143 in words is "eleven trillion, twelve billion, one hundred million, one hundred one thousand, one hundred forty-three".