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11012103113 = 111001100283
BaseRepresentation
bin10100100000101111…
…10101101111001001
31001102110012210120212
422100113311233021
5140023044244423
65020415330505
7536614221614
oct122027655711
931373183525
1011012103113
114741055070
122173b20a35
1310665a455b
1476674117b
15446b80578
hex2905f5bc9

11012103113 has 4 divisors (see below), whose sum is σ = 12013203408. Its totient is φ = 10011002820.

The previous prime is 11012103077. The next prime is 11012103119. The reversal of 11012103113 is 31130121011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11012103113 - 210 = 11012102089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11012103119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500550131 + ... + 500550152.

It is an arithmetic number, because the mean of its divisors is an integer number (3003300852).

Almost surely, 211012103113 is an apocalyptic number.

It is an amenable number.

11012103113 is a deficient number, since it is larger than the sum of its proper divisors (1001100295).

11012103113 is a wasteful number, since it uses less digits than its factorization.

11012103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001100294.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 11012103113 its reverse (31130121011), we get a palindrome (42142224124).

The spelling of 11012103113 in words is "eleven billion, twelve million, one hundred three thousand, one hundred thirteen".

Divisors: 1 11 1001100283 11012103113