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110121102079949 is a prime number
BaseRepresentation
bin11001000010011110010001…
…001010111111011111001101
3112102220110210221110212002102
4121002132101022333133031
5103413211004113024244
61030112534053404445
732123662365310202
oct3102362112773715
9472813727425072
10110121102079949
11320a7108300294
121042625a339725
13495a4b58b712c
141d29c657a7ca9
15cae78131054e
hex6427912bf7cd

110121102079949 has 2 divisors, whose sum is σ = 110121102079950. Its totient is φ = 110121102079948.

The previous prime is 110121102079927. The next prime is 110121102079951. The reversal of 110121102079949 is 949970201121011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96733421149225 + 13387680930724 = 9835315^2 + 3658918^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110121102079949 is a prime.

Together with 110121102079951, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110121102079999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55060551039974 + 55060551039975.

It is an arithmetic number, because the mean of its divisors is an integer number (55060551039975).

Almost surely, 2110121102079949 is an apocalyptic number.

It is an amenable number.

110121102079949 is a deficient number, since it is larger than the sum of its proper divisors (1).

110121102079949 is an equidigital number, since it uses as much as digits as its factorization.

110121102079949 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 47.

The spelling of 110121102079949 in words is "one hundred ten trillion, one hundred twenty-one billion, one hundred two million, seventy-nine thousand, nine hundred forty-nine".