Base | Representation |
---|---|
bin | 10100100000101111… |
… | …11000001110010111 |
3 | 1001102110020022120021 |
4 | 22100113320032113 |
5 | 140023100111203 |
6 | 5020415450011 |
7 | 536614263412 |
oct | 122027701627 |
9 | 31373208507 |
10 | 11012113303 |
11 | 4741061794 |
12 | 2173b26907 |
13 | 10665a9099 |
14 | 766744b79 |
15 | 446b835bd |
hex | 2905f8397 |
11012113303 has 2 divisors, whose sum is σ = 11012113304. Its totient is φ = 11012113302.
The previous prime is 11012113297. The next prime is 11012113327. The reversal of 11012113303 is 30331121011.
11012113303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012113303 - 217 = 11011982231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11012113393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506056651 + 5506056652.
It is an arithmetic number, because the mean of its divisors is an integer number (5506056652).
Almost surely, 211012113303 is an apocalyptic number.
11012113303 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012113303 is an equidigital number, since it uses as much as digits as its factorization.
11012113303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11012113303 its reverse (30331121011), we get a palindrome (41343234314).
The spelling of 11012113303 in words is "eleven billion, twelve million, one hundred thirteen thousand, three hundred three".
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