110122001113 has 2 divisors, whose sum is σ = 110122001114. Its totient is φ = 110122001112.

The previous prime is 110122001089. The next prime is 110122001203. The reversal of 110122001113 is 311100221011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107855098569 + 2266902544 = 328413^2 + 47612^2 .

It is an emirp because it is prime and its reverse (311100221011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110122001113 - 2¹³ = 110121992921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110122001093 and 110122001102.

It is not a weakly prime, because it can be changed into another prime (110122005113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55061000556 + 55061000557.

It is an arithmetic number, because the mean of its divisors is an integer number (55061000557).

Almost surely, 2^110122001113 is an apocalyptic number.

It is an amenable number.

110122001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110122001113 is an equidigital number, since it uses as much as digits as its factorization.

110122001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 110122001113 its reverse (311100221011), we get a palindrome (421222222124).

The spelling of 110122001113 in words is "one hundred ten billion, one hundred twenty-two million, one thousand, one hundred thirteen".