11012203113 has 4 divisors (see below), whose sum is σ = 14682937488. Its totient is φ = 7341468740.

The previous prime is 11012203109. The next prime is 11012203127. The reversal of 11012203113 is 31130221011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31130221011 = 3 ⋅10376740337.

It is a cyclic number.

It is not a de Polignac number, because 11012203113 - 2² = 11012203109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11012203092 and 11012203101.

It is not an unprimeable number, because it can be changed into a prime (11012203133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1835367183 + ... + 1835367188.

It is an arithmetic number, because the mean of its divisors is an integer number (3670734372).

Almost surely, 2^11012203113 is an apocalyptic number.

It is an amenable number.

11012203113 is a deficient number, since it is larger than the sum of its proper divisors (3670734375).

11012203113 is an equidigital number, since it uses as much as digits as its factorization.

11012203113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3670734374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11012203113 its reverse (31130221011), we get a palindrome (42142424124).

The spelling of 11012203113 in words is "eleven billion, twelve million, two hundred three thousand, one hundred thirteen".