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11012210341 = 111001110031
BaseRepresentation
bin10100100000110000…
…01111111010100101
31001102110102020200021
422100120033322211
5140023111212331
65020421515141
7536615146336
oct122030177245
931373366607
1011012210341
114741118690
122173b72ab1
1310666112c2
1476676c28d
15446ba2211
hex29060fea5

11012210341 has 4 divisors (see below), whose sum is σ = 12013320384. Its totient is φ = 10011100300.

The previous prime is 11012210329. The next prime is 11012210351. The reversal of 11012210341 is 14301221011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11012210341 - 215 = 11012177573 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11012210351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500555005 + ... + 500555026.

It is an arithmetic number, because the mean of its divisors is an integer number (3003330096).

Almost surely, 211012210341 is an apocalyptic number.

11012210341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11012210341 is a deficient number, since it is larger than the sum of its proper divisors (1001110043).

11012210341 is a wasteful number, since it uses less digits than its factorization.

11012210341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1001110042.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11012210341 its reverse (14301221011), we get a palindrome (25313431352).

The spelling of 11012210341 in words is "eleven billion, twelve million, two hundred ten thousand, three hundred forty-one".

Divisors: 1 11 1001110031 11012210341