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11012260262953 is a prime number
BaseRepresentation
bin1010000000111111110111…
…0111000111010000101001
31102222202120100111120022111
42200033331313013100221
52420411102111403303
635230543523322321
72214416034535225
oct240177567072051
942882510446274
1011012260262953
113566300913a34
12129a2bb8203a1
1361b5b4482711
142a0dd3981785
151416c2bd9b6d
hexa03fddc7429

11012260262953 has 2 divisors, whose sum is σ = 11012260262954. Its totient is φ = 11012260262952.

The previous prime is 11012260262951. The next prime is 11012260263049. The reversal of 11012260262953 is 35926206221011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10982118789184 + 30141473769 = 3313928^2 + 173613^2 .

It is a cyclic number.

It is not a de Polignac number, because 11012260262953 - 21 = 11012260262951 is a prime.

Together with 11012260262951, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11012260262951) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506130131476 + 5506130131477.

It is an arithmetic number, because the mean of its divisors is an integer number (5506130131477).

Almost surely, 211012260262953 is an apocalyptic number.

It is an amenable number.

11012260262953 is a deficient number, since it is larger than the sum of its proper divisors (1).

11012260262953 is an equidigital number, since it uses as much as digits as its factorization.

11012260262953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 77760, while the sum is 40.

Adding to 11012260262953 its reverse (35926206221011), we get a palindrome (46938466483964).

The spelling of 11012260262953 in words is "eleven trillion, twelve billion, two hundred sixty million, two hundred sixty-two thousand, nine hundred fifty-three".