Base | Representation |
---|---|
bin | 1010000000111111110111… |
… | …0111101001111111011111 |
3 | 1102222202120100202210110110 |
4 | 2200033331313221333133 |
5 | 2420411102130431330 |
6 | 35230543530341103 |
7 | 2214416036000046 |
oct | 240177567517737 |
9 | 42882510683413 |
10 | 11012260405215 |
11 | 3566300a00903 |
12 | 129a2bb88a793 |
13 | 61b5b45023b4 |
14 | 2a0dd39bb55d |
15 | 1416c2c16db0 |
hex | a03fdde9fdf |
11012260405215 has 32 divisors (see below), whose sum is σ = 17656296799680. Its totient is φ = 5860991545344.
The previous prime is 11012260405141. The next prime is 11012260405217. The reversal of 11012260405215 is 51250406221011.
It is not a de Polignac number, because 11012260405215 - 27 = 11012260405087 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11012260405217) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13496877 + ... + 14289513.
It is an arithmetic number, because the mean of its divisors is an integer number (551759274990).
Almost surely, 211012260405215 is an apocalyptic number.
11012260405215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11012260405215 is a deficient number, since it is larger than the sum of its proper divisors (6644036394465).
11012260405215 is an equidigital number, since it uses as much as digits as its factorization.
11012260405215 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 794571.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 11012260405215 its reverse (51250406221011), we get a palindrome (62262666626226).
The spelling of 11012260405215 in words is "eleven trillion, twelve billion, two hundred sixty million, four hundred five thousand, two hundred fifteen".
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