Base | Representation |
---|---|
bin | 1010000001000000000110… |
… | …0010101010110001111011 |
3 | 1102222202201122200202110201 |
4 | 2200100001202222301323 |
5 | 2420411213413343113 |
6 | 35230554011023031 |
7 | 2214420414436354 |
oct | 240200142526173 |
9 | 42882648622421 |
10 | 11012322012283 |
11 | 356633275a139 |
12 | 129a31843aa77 |
13 | 61b5c41c2997 |
14 | 2a0ddbc56d2b |
15 | 1416c8335cdd |
hex | a04018aac7b |
11012322012283 has 2 divisors, whose sum is σ = 11012322012284. Its totient is φ = 11012322012282.
The previous prime is 11012322012281. The next prime is 11012322012337. The reversal of 11012322012283 is 38221022321011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11012322012283 - 21 = 11012322012281 is a prime.
It is a super-2 number, since 2×110123220122832 (a number of 27 digits) contains 22 as substring.
Together with 11012322012281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11012322012281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506161006141 + 5506161006142.
It is an arithmetic number, because the mean of its divisors is an integer number (5506161006142).
Almost surely, 211012322012283 is an apocalyptic number.
11012322012283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11012322012283 is an equidigital number, since it uses as much as digits as its factorization.
11012322012283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 11012322012283 its reverse (38221022321011), we get a palindrome (49233344333294).
The spelling of 11012322012283 in words is "eleven trillion, twelve billion, three hundred twenty-two million, twelve thousand, two hundred eighty-three".
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