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11013000213 = 33671000071
BaseRepresentation
bin10100100000110110…
…10000110000010101
31001102111220101011210
422100123100300111
5140023312001323
65020450452033
7536624646225
oct122033206025
931374811153
1011013000213
114741608076
122174294019
131066829997
147668d6085
15446cab293
hex2906d0c15

11013000213 has 4 divisors (see below), whose sum is σ = 14684000288. Its totient is φ = 7342000140.

The previous prime is 11013000211. The next prime is 11013000247. The reversal of 11013000213 is 31200031011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11013000213 - 21 = 11013000211 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11013000211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1835500033 + ... + 1835500038.

It is an arithmetic number, because the mean of its divisors is an integer number (3671000072).

Almost surely, 211013000213 is an apocalyptic number.

It is an amenable number.

11013000213 is a deficient number, since it is larger than the sum of its proper divisors (3671000075).

11013000213 is an equidigital number, since it uses as much as digits as its factorization.

11013000213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3671000074.

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 11013000213 its reverse (31200031011), we get a palindrome (42213031224).

The spelling of 11013000213 in words is "eleven billion, thirteen million, two hundred thirteen", and thus it is an aban number.

Divisors: 1 3 3671000071 11013000213