11013000421 has 2 divisors, whose sum is σ = 11013000422. Its totient is φ = 11013000420.

The previous prime is 11013000407. The next prime is 11013000431. The reversal of 11013000421 is 12400031011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9017591521 + 1995408900 = 94961^2 + 44670^2 .

It is an emirp because it is prime and its reverse (12400031011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11013000421 - 2⁵ = 11013000389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11013000431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506500210 + 5506500211.

It is an arithmetic number, because the mean of its divisors is an integer number (5506500211).

Almost surely, 2^11013000421 is an apocalyptic number.

It is an amenable number.

11013000421 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013000421 is an equidigital number, since it uses as much as digits as its factorization.

11013000421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11013000421 its reverse (12400031011), we get a palindrome (23413031432).

The spelling of 11013000421 in words is "eleven billion, thirteen million, four hundred twenty-one", and thus it is an aban number.