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110130232412020 = 2255506511620601
BaseRepresentation
bin11001000010100110110001…
…011000011100011101110100
3112102221100101020210210002111
4121002212301120130131310
5103413333203444141040
61030121044052220404
732124434552664142
oct3102466130343564
9472840336723074
10110130232412020
11320aaa7311a977
1210427b8800a704
13495b30c36b0a2
141d2a490228592
15caeb17b83dea
hex6429b161c774

110130232412020 has 12 divisors (see below), whose sum is σ = 231273488065284. Its totient is φ = 44052092964800.

The previous prime is 110130232411999. The next prime is 110130232412033. The reversal of 110130232412020 is 20214232031011.

It can be written as a sum of positive squares in 2 ways, for example, as 55537699379044 + 54592533032976 = 7452362^2 + 7388676^2 .

It is a super-2 number, since 2×1101302324120202 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110130232411982 and 110130232412000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2753255810281 + ... + 2753255810320.

It is an arithmetic number, because the mean of its divisors is an integer number (19272790672107).

Almost surely, 2110130232412020 is an apocalyptic number.

110130232412020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

110130232412020 is an abundant number, since it is smaller than the sum of its proper divisors (121143255653264).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110130232412020 is a wasteful number, since it uses less digits than its factorization.

110130232412020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5506511620610 (or 5506511620608 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 110130232412020 its reverse (20214232031011), we get a palindrome (130344464443031).

The spelling of 110130232412020 in words is "one hundred ten trillion, one hundred thirty billion, two hundred thirty-two million, four hundred twelve thousand, twenty".

Divisors: 1 2 4 5 10 20 5506511620601 11013023241202 22026046482404 27532558103005 55065116206010 110130232412020