Base | Representation |
---|---|
bin | 10100100000110111… |
… | …01001100110111101 |
3 | 1001102112002112211011 |
4 | 22100123221212331 |
5 | 140023323231023 |
6 | 5020452555221 |
7 | 536625552064 |
oct | 122033514675 |
9 | 31375075734 |
10 | 11013102013 |
11 | 4741677601 |
12 | 2174322b11 |
13 | 1066864114 |
14 | 7669211db |
15 | 446ccb50d |
hex | 2906e99bd |
11013102013 has 4 divisors (see below), whose sum is σ = 11035532448. Its totient is φ = 10990671580.
The previous prime is 11013101999. The next prime is 11013102041. The reversal of 11013102013 is 31020131011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11013102013 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11013101984 and 11013102002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11013102913) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11214481 + ... + 11215462.
It is an arithmetic number, because the mean of its divisors is an integer number (2758883112).
Almost surely, 211013102013 is an apocalyptic number.
It is an amenable number.
11013102013 is a deficient number, since it is larger than the sum of its proper divisors (22430435).
11013102013 is an equidigital number, since it uses as much as digits as its factorization.
11013102013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22430434.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11013102013 its reverse (31020131011), we get a palindrome (42033233024).
The spelling of 11013102013 in words is "eleven billion, thirteen million, one hundred two thousand, thirteen".
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