Search a number
-
+
1101310320013 is a prime number
BaseRepresentation
bin10000000001101011001…
…101011101110110001101
310220021200012122220212121
4100001223031131312031
5121020440420220023
62201533542132541
7142365332156341
oct20015315356615
93807605586777
101101310320013
11395076a678a2
12159536721151
137cb123b7667
143b437513621
151d9aaa2dd5d
hex1006b35dd8d

1101310320013 has 2 divisors, whose sum is σ = 1101310320014. Its totient is φ = 1101310320012.

The previous prime is 1101310319957. The next prime is 1101310320029. The reversal of 1101310320013 is 3100230131011.

It is an a-pointer prime, because the next prime (1101310320029) can be obtained adding 1101310320013 to its sum of digits (16).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1088460283849 + 12850036164 = 1043293^2 + 113358^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1101310320013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1101310326013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550655160006 + 550655160007.

It is an arithmetic number, because the mean of its divisors is an integer number (550655160007).

Almost surely, 21101310320013 is an apocalyptic number.

It is an amenable number.

1101310320013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1101310320013 is an equidigital number, since it uses as much as digits as its factorization.

1101310320013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1101310320013 its reverse (3100230131011), we get a palindrome (4201540451024).

The spelling of 1101310320013 in words is "one trillion, one hundred one billion, three hundred ten million, three hundred twenty thousand, thirteen".