Base | Representation |
---|---|
bin | 10000000001101011001… |
… | …101011101110110001101 |
3 | 10220021200012122220212121 |
4 | 100001223031131312031 |
5 | 121020440420220023 |
6 | 2201533542132541 |
7 | 142365332156341 |
oct | 20015315356615 |
9 | 3807605586777 |
10 | 1101310320013 |
11 | 395076a678a2 |
12 | 159536721151 |
13 | 7cb123b7667 |
14 | 3b437513621 |
15 | 1d9aaa2dd5d |
hex | 1006b35dd8d |
1101310320013 has 2 divisors, whose sum is σ = 1101310320014. Its totient is φ = 1101310320012.
The previous prime is 1101310319957. The next prime is 1101310320029. The reversal of 1101310320013 is 3100230131011.
It is an a-pointer prime, because the next prime (1101310320029) can be obtained adding 1101310320013 to its sum of digits (16).
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1088460283849 + 12850036164 = 1043293^2 + 113358^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1101310320013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1101310326013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550655160006 + 550655160007.
It is an arithmetic number, because the mean of its divisors is an integer number (550655160007).
Almost surely, 21101310320013 is an apocalyptic number.
It is an amenable number.
1101310320013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1101310320013 is an equidigital number, since it uses as much as digits as its factorization.
1101310320013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 1101310320013 its reverse (3100230131011), we get a palindrome (4201540451024).
The spelling of 1101310320013 in words is "one trillion, one hundred one billion, three hundred ten million, three hundred twenty thousand, thirteen".
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