110131331201 has 2 divisors, whose sum is σ = 110131331202. Its totient is φ = 110131331200.

The previous prime is 110131331159. The next prime is 110131331203. The reversal of 110131331201 is 102133131011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88670546176 + 21460785025 = 297776^2 + 146495^2 .

It is an emirp because it is prime and its reverse (102133131011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110131331201 - 2³⁴ = 92951462017 is a prime.

It is a super-2 number, since 2×110131331201² (a number of 23 digits) contains 22 as substring.

Together with 110131331203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110131331201.

It is not a weakly prime, because it can be changed into another prime (110131331203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55065665600 + 55065665601.

It is an arithmetic number, because the mean of its divisors is an integer number (55065665601).

Almost surely, 2^110131331201 is an apocalyptic number.

It is an amenable number.

110131331201 is a deficient number, since it is larger than the sum of its proper divisors (1).

110131331201 is an equidigital number, since it uses as much as digits as its factorization.

110131331201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 110131331201 its reverse (102133131011), we get a palindrome (212264462212).

The spelling of 110131331201 in words is "one hundred ten billion, one hundred thirty-one million, three hundred thirty-one thousand, two hundred one".