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110132014 = 255066007
BaseRepresentation
bin1101001000001…
…11101100101110
321200020021201111
412210013230232
5211143211024
614532302234
72505051406
oct644075456
9250207644
10110132014
11571918a3
1230a7197a
1319a80495
14108ab806
159a06a94
hex6907b2e

110132014 has 4 divisors (see below), whose sum is σ = 165198024. Its totient is φ = 55066006.

The previous prime is 110132003. The next prime is 110132047. The reversal of 110132014 is 410231011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 410231011 = 3167129533.

It is a super-3 number, since 3×1101320143 (a number of 25 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110131985 and 110132003.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27533002 + ... + 27533005.

It is an arithmetic number, because the mean of its divisors is an integer number (41299506).

Almost surely, 2110132014 is an apocalyptic number.

110132014 is a deficient number, since it is larger than the sum of its proper divisors (55066010).

110132014 is an equidigital number, since it uses as much as digits as its factorization.

110132014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55066009.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 110132014 is about 10494.3801150902. The cubic root of 110132014 is about 479.3335861999. Note that the first 3 decimals are identical.

Adding to 110132014 its reverse (410231011), we get a palindrome (520363025).

The spelling of 110132014 in words is "one hundred ten million, one hundred thirty-two thousand, fourteen".

Divisors: 1 2 55066007 110132014