Base | Representation |
---|---|
bin | 1010000001000011011010… |
… | …0110001000000111000110 |
3 | 1102222212000200120110210001 |
4 | 2200100312212020013012 |
5 | 2420420024300030202 |
6 | 35231222204551514 |
7 | 2214451443240262 |
oct | 240206646100706 |
9 | 42885020513701 |
10 | 11013212111302 |
11 | 356674a139765 |
12 | 129a52655259a |
13 | 61b7067308ab |
14 | 2a10841570a2 |
15 | 14172b558d87 |
hex | a04369881c6 |
11013212111302 has 4 divisors (see below), whose sum is σ = 16519818166956. Its totient is φ = 5506606055650.
The previous prime is 11013212111267. The next prime is 11013212111311. The reversal of 11013212111302 is 20311121231011.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×110132121113022 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11013212111302.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2753303027824 + ... + 2753303027827.
It is an arithmetic number, because the mean of its divisors is an integer number (4129954541739).
Almost surely, 211013212111302 is an apocalyptic number.
11013212111302 is a deficient number, since it is larger than the sum of its proper divisors (5506606055654).
11013212111302 is an equidigital number, since it uses as much as digits as its factorization.
11013212111302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5506606055653.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 11013212111302 its reverse (20311121231011), we get a palindrome (31324333342313).
The spelling of 11013212111302 in words is "eleven trillion, thirteen billion, two hundred twelve million, one hundred eleven thousand, three hundred two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •