Base | Representation |
---|---|
bin | 1010000001000011100100… |
… | …0011110101111001011010 |
3 | 1102222212010120100222021210 |
4 | 2200100321003311321122 |
5 | 2420420120341033300 |
6 | 35231230243043550 |
7 | 2214452454534201 |
oct | 240207103657132 |
9 | 42885116328253 |
10 | 11013253455450 |
11 | 3566770508184 |
12 | 129a5383705b6 |
13 | 61b71217819c |
14 | 2a108983a238 |
15 | 14172eec4050 |
hex | a04390f5e5a |
11013253455450 has 48 divisors (see below), whose sum is σ = 27313085886336. Its totient is φ = 2936844220800.
The previous prime is 11013253455439. The next prime is 11013253455539. The reversal of 11013253455450 is 5455435231011.
It is a junction number, because it is equal to n+sod(n) for n = 11013253455399 and 11013253455408.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 27252870 + ... + 27654030.
It is an arithmetic number, because the mean of its divisors is an integer number (569022622632).
Almost surely, 211013253455450 is an apocalyptic number.
11013253455450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11013253455450 is an abundant number, since it is smaller than the sum of its proper divisors (16299832430886).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11013253455450 is a wasteful number, since it uses less digits than its factorization.
11013253455450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 584199 (or 584194 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 11013253455450 its reverse (5455435231011), we get a palindrome (16468688686461).
The spelling of 11013253455450 in words is "eleven trillion, thirteen billion, two hundred fifty-three million, four hundred fifty-five thousand, four hundred fifty".
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