Base | Representation |
---|---|
bin | 10100100000111000… |
… | …11100111010001111 |
3 | 1001102112111020001202 |
4 | 22100130130322033 |
5 | 140023401442033 |
6 | 5020501300115 |
7 | 536630415521 |
oct | 122034347217 |
9 | 31375436052 |
10 | 11013312143 |
11 | 4741800469 |
12 | 217440463b |
13 | 1066908962 |
14 | 766977a11 |
15 | 446d1d8e8 |
hex | 29071ce8f |
11013312143 has 2 divisors, whose sum is σ = 11013312144. Its totient is φ = 11013312142.
The previous prime is 11013312137. The next prime is 11013312169. The reversal of 11013312143 is 34121331011.
11013312143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11013312143 - 220 = 11012263567 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013312103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506656071 + 5506656072.
It is an arithmetic number, because the mean of its divisors is an integer number (5506656072).
Almost surely, 211013312143 is an apocalyptic number.
11013312143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013312143 is an equidigital number, since it uses as much as digits as its factorization.
11013312143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 11013312143 its reverse (34121331011), we get a palindrome (45134643154).
The spelling of 11013312143 in words is "eleven billion, thirteen million, three hundred twelve thousand, one hundred forty-three".
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