Base | Representation |
---|---|
bin | 1010000001000011110111… |
… | …0100000010110100001101 |
3 | 1102222212100010102102102212 |
4 | 2200100331310002310031 |
5 | 2420420301244401031 |
6 | 35231242212200205 |
7 | 2214454443415046 |
oct | 240207564026415 |
9 | 42885303372385 |
10 | 11013333200141 |
11 | 3566801524588 |
12 | 129a55b009065 |
13 | 61b7258492ac |
14 | 2a10962778cd |
15 | 141736ec712b |
hex | a043dd02d0d |
11013333200141 has 2 divisors, whose sum is σ = 11013333200142. Its totient is φ = 11013333200140.
The previous prime is 11013333200069. The next prime is 11013333200203. The reversal of 11013333200141 is 14100233331011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10970529728041 + 42803472100 = 3312179^2 + 206890^2 .
It is an emirp because it is prime and its reverse (14100233331011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11013333200141 - 214 = 11013333183757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11013333200641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506666600070 + 5506666600071.
It is an arithmetic number, because the mean of its divisors is an integer number (5506666600071).
Almost surely, 211013333200141 is an apocalyptic number.
It is an amenable number.
11013333200141 is a deficient number, since it is larger than the sum of its proper divisors (1).
11013333200141 is an equidigital number, since it uses as much as digits as its factorization.
11013333200141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11013333200141 its reverse (14100233331011), we get a palindrome (25113566531152).
The spelling of 11013333200141 in words is "eleven trillion, thirteen billion, three hundred thirty-three million, two hundred thousand, one hundred forty-one".
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