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11013405455215 = 52202681091043
BaseRepresentation
bin1010000001000100001000…
…0111101011001101101111
31102222212112011101100202201
42200101002013223031233
52420420423244031330
635231253313002331
72214456311523202
oct240210207531557
942885464340681
1011013405455215
113566839295919
12129a57b2533a7
1361b7377c7387
142a10a1ac5939
1514173d4eaeca
hexa04421eb36f

11013405455215 has 4 divisors (see below), whose sum is σ = 13216086546264. Its totient is φ = 8810724364168.

The previous prime is 11013405455081. The next prime is 11013405455249. The reversal of 11013405455215 is 51255450431011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11013405455215 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1101340545517 + ... + 1101340545526.

It is an arithmetic number, because the mean of its divisors is an integer number (3304021636566).

Almost surely, 211013405455215 is an apocalyptic number.

11013405455215 is a deficient number, since it is larger than the sum of its proper divisors (2202681091049).

11013405455215 is an equidigital number, since it uses as much as digits as its factorization.

11013405455215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2202681091048.

The product of its (nonzero) digits is 60000, while the sum is 37.

Adding to 11013405455215 its reverse (51255450431011), we get a palindrome (62268855886226).

The spelling of 11013405455215 in words is "eleven trillion, thirteen billion, four hundred five million, four hundred fifty-five thousand, two hundred fifteen".

Divisors: 1 5 2202681091043 11013405455215