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110134244053 is a prime number
BaseRepresentation
bin110011010010010000…
…0110011001011010101
3101112021110000021121001
41212210200303023111
53301023331302203
6122332303023301
710646141425351
oct1464440631325
9345243007531
10110134244053
1142786a00709
121941789ab31
13a502270362
14548ad6a461
152ce8cb391d
hex19a48332d5

110134244053 has 2 divisors, whose sum is σ = 110134244054. Its totient is φ = 110134244052.

The previous prime is 110134244041. The next prime is 110134244063. The reversal of 110134244053 is 350442431011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109943306929 + 190937124 = 331577^2 + 13818^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110134244053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110134244023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55067122026 + 55067122027.

It is an arithmetic number, because the mean of its divisors is an integer number (55067122027).

Almost surely, 2110134244053 is an apocalyptic number.

It is an amenable number.

110134244053 is a deficient number, since it is larger than the sum of its proper divisors (1).

110134244053 is an equidigital number, since it uses as much as digits as its factorization.

110134244053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 110134244053 its reverse (350442431011), we get a palindrome (460576675064).

The spelling of 110134244053 in words is "one hundred ten billion, one hundred thirty-four million, two hundred forty-four thousand, fifty-three".