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11013450654599 is a prime number
BaseRepresentation
bin1010000001000100010011…
…0100000110001110000111
31102222212122022102201122222
42200101010310012032013
52420421021331421344
635231302005442555
72214460400644631
oct240210464061607
942885568381588
1011013450654599
113566861857888
12129a59241045b
1361b743c91683
142a10a7acda51
151417424785ee
hexa0444d06387

11013450654599 has 2 divisors, whose sum is σ = 11013450654600. Its totient is φ = 11013450654598.

The previous prime is 11013450654589. The next prime is 11013450654601. The reversal of 11013450654599 is 99545605431011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11013450654599 is a prime.

Together with 11013450654601, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11013450654599.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11013450654589) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5506725327299 + 5506725327300.

It is an arithmetic number, because the mean of its divisors is an integer number (5506725327300).

Almost surely, 211013450654599 is an apocalyptic number.

11013450654599 is a deficient number, since it is larger than the sum of its proper divisors (1).

11013450654599 is an equidigital number, since it uses as much as digits as its factorization.

11013450654599 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916000, while the sum is 53.

The spelling of 11013450654599 in words is "eleven trillion, thirteen billion, four hundred fifty million, six hundred fifty-four thousand, five hundred ninety-nine".