110140213 has 4 divisors (see below), whose sum is σ = 110270188. Its totient is φ = 110010240.

The previous prime is 110140193. The next prime is 110140267. The reversal of 110140213 is 312041011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15311569 + 94828644 = 3913^2 + 9738^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110140213 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110140193 and 110140202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110140013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63708 + ... + 65413.

It is an arithmetic number, because the mean of its divisors is an integer number (27567547).

Almost surely, 2^110140213 is an apocalyptic number.

It is an amenable number.

110140213 is a deficient number, since it is larger than the sum of its proper divisors (129975).

110140213 is an equidigital number, since it uses as much as digits as its factorization.

110140213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129974.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 110140213 is about 10494.7707454713. The cubic root of 110140213 is about 479.3454808901.

Adding to 110140213 its reverse (312041011), we get a palindrome (422181224).

It can be divided in two parts, 1101 and 40213, that added together give a palindrome (41314).

The spelling of 110140213 in words is "one hundred ten million, one hundred forty thousand, two hundred thirteen".